JEE Advanced levelSingle correct optionDifficulty 3 of 3qc220
A solution contains 0.0100mol each of BaX2+, SrX2+ and CaX2+. It is treated successively with (1) KX2CrOX4 in acetic acid buffer, giving BaCrOX4; (2) (NHX4)X2SOX4 on warming, giving SrSOX4; (3) (NHX4)X2CX2OX4 giving CaCX2OX4⋅HX2O (each filtered off, precipitation complete). Molar masses: BaCrOX4 253, SrSOX4 183.6, CaCX2OX4⋅HX2O 146 g/mol. The total mass of the three precipitates is
A3.30g
B5.83g
C3.99g
D5.65g
Answer: B
Each step is 0.0100 mol: 0.0100×(253+183.6+146)=5.826g, i.e. 5.83g. Omitting the water of crystallisation of calcium oxalate gives 5.65 g, and leaving out one salt gives the smaller values.