JEE Advanced levelSingle correct optionDifficulty 3 of 3qc156
A black sulphide X from group II (precipitated with HX2S in 0.3 M HCl) does not dissolve in yellow ammonium sulphide but dissolves in hot dilute HNOX3. The nitrate solution gives no precipitate with dilute HX2SOX4, and a white precipitate with excess NHX4OH whose filtrate is colourless. The white precipitate gives a black deposit with alkaline sodium stannite. How many moles of stannite [Sn(OH)X4]X2− are oxidised per mole of the metal ion being reduced?
AX is BiX2SX3; 3 mol of stannite per mol of BiX3+
BX is PbS; 1.5 mol of stannite per mol of PbX2+
CX is CuS; 1 mol of stannite per mol of CuX2+
DX is BiX2SX3; 1.5 mol of stannite per mol of BiX3+
Answer: D
No PbSOX4 and a colourless ammoniacal filtrate (no blue) exclude PbX2+ and CuX2+; the white Bi(OH)X3 is reduced to black bismuth. Bi goes +3 to 0 (3 electrons) while Sn goes +2 to +4 (2 electrons): 2Bi(OH)X3+3[Sn(OH)X4]X2−2Bi+3[Sn(OH)X6]X2−. This is 3 stannite per 2 Bi, i.e. 1.5 per Bi.