Match the reaction in List I with the colour of the precipitate in List II. List I: (i) I- with Pb(NO3)2; (ii) S^2- with Pb(NO3)2; (iii) Br- with AgNO3; (iv) SO4^2- with BaCl2. List II: (p) black; (q) bright yellow; (r) pale yellow (cream); (s) white.

(i)-(r), (ii)-(p), (iii)-(q), (iv)-(s)

(i)-(q), (ii)-(s), (iii)-(r), (iv)-(p)

(i)-(s), (ii)-(p), (iii)-(q), (iv)-(r)

JEE Main levelSingle correct optionDifficulty 2 of 3qa212

Match the reaction in List I with the colour of the precipitate in List II. List I: (i) $I X^{-}$ with $Pb (NO X_{3}) X_{2}$ ; (ii) $S X^{2 -}$ with $Pb (NO X_{3}) X_{2}$ ; (iii) $Br X^{-}$ with $AgNO X_{3}$ ; (iv) $SO X_{4} X^{2 -}$ with $BaCl X_{2}$ . List II: (p) black; (q) bright yellow; (r) pale yellow (cream); (s) white.

PbI X_{2}

is bright yellow,

PbS

is black,

AgBr

is pale yellow (cream) and

BaSO X_{4}

is white. This gives (i)-(q), (ii)-(p), (iii)-(r), (iv)-(s).