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JEE Main levelSingle correct optionDifficulty 2 of 3qa193

Match the anion in List I with its confirmatory observation in List II. List I: (i) sulphate; (ii) phosphate; (iii) borate. List II: (p) canary yellow precipitate with ammonium molybdate in warm conc. ; (q) white precipitate with insoluble in dilute ; (r) green-edged flame on burning its ester with ethanol and conc. ; (s) black precipitate with lead acetate solution.

  1. A(i)-(q), (ii)-(p), (iii)-(r)
  2. B(i)-(r), (ii)-(p), (iii)-(q)
  3. C(i)-(q), (ii)-(r), (iii)-(p)
  4. D(i)-(p), (ii)-(q), (iii)-(r)

Answer: A

Sulphate gives insoluble white (q). Phosphate gives yellow ammonium phosphomolybdate (p). Borate, as boric acid, forms a volatile ester that burns with a green-edged flame (r). Black lead precipitate (s) is not matched to any of these three anions.
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