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NEET levelSingle correct optionDifficulty 1 of 3qa167

A salt on warming with dilute $H X_{2} SO X_{4}$ evolves a gas that turns a filter paper moistened with lead acetate black. The anion present is

A $CO X_{3} X^{2 -}$
B $SO X_{3} X^{2 -}$
C $S X^{2 -}$
D $NO X_{2} X^{-}$

Answer: C

Sulphide liberates

H X_{2} S

with dilute acid.

H X_{2} S + Pb (CH X_{3} COO) X_{2} PbS + 2 CH X_{3} COOH

forms black lead sulphide on the paper. Sulphite, carbonate and nitrite give

SO X_{2}

,

CO X_{2}

and

NO

/

NO X_{2}

which do not blacken lead acetate paper.

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