JEE Main levelNumerical answerDifficulty 2 of 3qa141
A 2.00 g solid mixture contains only NaCl and NaBr, with NaCl forming 35.0% of the mass. The mixture is dissolved in water and treated with excess AgNOX3 solution. The precipitate is shaken with excess dilute aqueous ammonia, which dissolves all the AgCl (assume AgBr stays completely undissolved), and then filtered. Find the mass of the undissolved residue in grams, to two decimal places. (Na 23, Cl 35.5, Br 80, Ag 108.)
Numerical answer type, answer in g, tolerance 0.01.
Answer: 2.37 g
The residue is AgBr. Mass of NaBr = 2.00−0.700=1.300g, molar mass 103, so n=0.012621mol. AgBr has molar mass 188, so mass =0.012621×188=2.3728g≈2.37g.