The two compounds shown condense through one amide link, with loss of one molecule of water. Which of the structures shown is the product fragment (one amide bond, free end groups) on the route to nylon 6,6?

AStructure A
BStructure B
CStructure C
DStructure D

Answer: C

One NH2 of hexane-1,6-diamine attacks one COOH of hexanedioic acid, forming one -CO-NH- bond and leaving a free NH2 and a free COOH to continue the chain. The correct product therefore has a six-carbon diamine part and a four-carbon-plus-two-carbonyl diacid part joined by an amide. An ester product would need an alcohol, and the other options change the carbon-chain lengths.

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