JEE Advanced levelSingle correct optionDifficulty 3 of 3pl026
In a free radical polymerisation the rate of polymerisation is Rp=k[M][I]1/2 and the average degree of polymerisation is proportional to [M]/[I]1/2, where I is the initiator. At fixed monomer concentration and temperature, the initiator concentration is made four times larger. Then
ARp becomes four times and the average degree of polymerisation becomes one quarter
BRp becomes twice and the average degree of polymerisation becomes half
CRp becomes twice and the average degree of polymerisation becomes twice
DRp becomes half and the average degree of polymerisation becomes twice
Answer: B
With [I]→4[I], 41/2=2. Rp is multiplied by 2 and the degree of polymerisation by 1/2: more radicals mean faster reaction but shorter chains.