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JEE Main levelOne or more correct optionsDifficulty 2 of 3pt209

In which of the following does the element show a maximum oxidation state equal to the total number of its valence electrons ( $n s$ plus $(n - 1) d$ )?

AMn in $Mn X_{2} O X_{7}$
BCr in $CrO X_{3}$
CFe in $Fe X_{2} O X_{3}$
DCu in $CuO$

Answer: A, B

Mn has 7 and Cr has 6 valence electrons, and these are reached in

Mn X_{2} O X_{7}

and

CrO X_{3}

. Fe has 8 but its common compounds show

+ 3

(and

+ 6

at most), and Cu has 11 valence electrons but shows only up to

+ 3

.

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