Element A has first ionisation energy 10.4 eV and electron affinity 3.6 eV; element B has 9.0 eV and 1.4 eV. Using Mulliken's definition chi_M = (IE + EA)/2 and the conversion chi_P = chi_M/2.8, the difference chi_A - chi_B on the Pauling scale is nearest to

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Element A has first ionisation energy 10.4 eV and electron affinity 3.6 eV; element B has 9.0 eV and 1.4 eV. Using Mulliken's definition $χ_{M} = (I E + E A) /2$ and the conversion $χ_{P} = χ_{M} /2.8$ , the difference $χ_{A} - χ_{B}$ on the Pauling scale is nearest to

A0.64
B1.80
C0.32
D1.29

Answer: A

χ_{M} (A) = (10.4 + 3.6) /2 = 7.0

eV and

χ_{M} (B) = (9.0 + 1.4) /2 = 5.2

eV. The difference is 1.8 eV, which on dividing by 2.8 gives 0.64. The value 1.80 omits the conversion, 0.32 divides by 5.6, and 1.29 is a wrong ratio.

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Element A has first ionisation energy 10.4 eV and electron affinity 3.6 eV; element B has 9.0 eV and 1.4 eV. Using Mulliken's definition χM​=(IE+EA)/2 and the conversion χP​=χM​/2.8, the difference χA​−χB​ on the Pauling scale is nearest to

Answer: A

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Element A has first ionisation energy 10.4 eV and electron affinity 3.6 eV; element B has 9.0 eV and 1.4 eV. Using Mulliken's definition $χ_{M} = (I E + E A) /2$ and the conversion $χ_{P} = χ_{M} /2.8$ , the difference $χ_{A} - χ_{B}$ on the Pauling scale is nearest to