Using the Hannay-Smyth relation, percent ionic character = 16|Deltachi| + 3.5|Deltachi|^2, bond Q has |Deltachi| = 1.8 and bond P has |Deltachi| = 0.9. The ratio (percent ionic character of Q) / (percent ionic character of P) is nearest to

JEE Advanced levelSingle correct optionDifficulty 3 of 3pt173

Using the Hannay-Smyth relation, percent ionic character $= 16∣Δ χ ∣ + 3.5∣Δ χ ∣^{2}$ , bond Q has $∣Δ χ ∣ = 1.8$ and bond P has $∣Δ χ ∣ = 0.9$ . The ratio (percent ionic character of Q) / (percent ionic character of P) is nearest to

For P:

16 (0.9) + 3.5 (0.81) = 17.24%

. For Q:

16 (1.8) + 3.5 (3.24) = 40.14%

. The ratio is

40.14/17.24 = 2.33

. The electronegativity differences are in the ratio 2, and the quadratic term pushes the ratio slightly above 2.