Answer: B
The 6s2 electrons of thallium are an inert pair, so Tl(III) is a strong oxidant. It oxidises I− to iodine, which combines with excess iodide as IX3X−, leaving Tl(I). The solid is therefore TlX+ IX3X−, with oxidation states +1 for Tl and −1/3 for each iodine.