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JEE Main levelSingle correct optionDifficulty 2 of 3pt169

The oxidation states of nitrogen in $N X_{2} H X_{4}$ , $NH X_{2} OH$ , $N X_{2} O$ and $NO X_{2} X^{-}$ increase in the order

A $NH X_{2} OH < N X_{2} H X_{4} < N X_{2} O < NO X_{2} X^{-}$
B $N X_{2} H X_{4} < NH X_{2} OH < N X_{2} O < NO X_{2} X^{-}$
C $N X_{2} H X_{4} < NH X_{2} OH < NO X_{2} X^{-} < N X_{2} O$
D $N X_{2} O < N X_{2} H X_{4} < NH X_{2} OH < NO X_{2} X^{-}$

Answer: B

The oxidation numbers of N are

- 2

in

N X_{2} H X_{4}

,

- 1

in

NH X_{2} OH

,

+ 1

in

N X_{2} O

and

+ 3

in

NO X_{2} X^{-}

. Arranged in increasing order this gives

N X_{2} H X_{4} < NH X_{2} OH < N X_{2} O < NO X_{2} X^{-}

.

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