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JEE Advanced levelSingle correct optionDifficulty 3 of 3pt149

A hydrogen atom in its first excited state () absorbs a photon of wavelength 100 nm and is ionised. Take and the ground-state ionisation energy of hydrogen as 13.6 eV. The kinetic energy of the ejected electron is

  1. A
  2. B
  3. C
  4. D

Answer: D

Photon energy = 1240/100 = 12.4 eV. Ionisation energy of is 13.6/4 = 3.4 eV. KE = 12.4 - 3.4 = 9.0 eV. Using 13.6 would give a negative value, and adding 3.4 gives the wrong 15.8.
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