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JEE Main levelSingle correct optionDifficulty 2 of 3pt138

The electron gain enthalpy of $F (g)$ is $- 328 kJ mo l^{- 1}$ . The enthalpy change for $2 F X^{-} (g) \to 2 F (g) + 2 e^{-}$ (2 mol) is

A $+ 164 kJ mo l^{- 1}$
B $+ 656 kJ mo l^{- 1}$
C $+ 328 kJ mo l^{- 1}$
D $- 656 kJ mo l^{- 1}$

Answer: B

Removing an electron from

F X^{-}

is the reverse of gain, +328 kJ per mol. For 2 mol, 2 x 328 = +656 kJ (energy absorbed).

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