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JEE Main levelSingle correct optionDifficulty 2 of 3pt128

Taking the ground-state ionisation energy of hydrogen as 13.6 eV, the energy required to remove the electron from $Li X^{2 +}$ in its ground state is

A122.4 eV
B54.4 eV
C81.6 eV
D40.8 eV

Answer: A

For a one-electron species the ground-state ionisation energy is

13.6 Z^{2}

eV. For

Li X^{2 +}

,

Z = 3

, so energy = 13.6 x 9 = 122.4 eV.

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