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The electron gain enthalpy of $Cl (g)$ is $- 349 kJ mo l^{- 1}$ . The energy that must be supplied to remove one mole of electrons from $Cl X^{-} (g)$ is therefore

A $+ 1251 kJ mo l^{- 1}$
B $0 kJ mo l^{- 1}$
C $+ 349 kJ mo l^{- 1}$
D $- 349 kJ mo l^{- 1}$

Answer: C

Removing the electron from

Cl X^{-} (g)

is the reverse of electron gain, so its enthalpy change has the same magnitude and opposite sign:

+ 349 kJ mo l^{- 1}

. The 1251 value is the ionisation enthalpy of neutral Cl.

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