Answer: A, B
Because the screening is identical (11.25), Z∗ differs by exactly ΔZ: 7.75−5.75=2.00. A higher Z∗ means a smaller radius, so SX2− is largest and CaX2+ smallest. The predicted ratio is Z∗(CaX2+)/Z∗(SX2−)=1.84, not 0.54. More protons make KX+ smaller than ClX−.