JEE Advanced levelSingle correct optionDifficulty 3 of 3pt094
Use the following rule set. Slater's rules: write the configuration in groups (1s)(2s,2p)(3s,3p)(3d)(4s,4p)(4d)(4f)(5s,5p)… For an electron in an ns or np group, every other electron in the same group contributes 0.35 (0.30 for the 1s group), every electron in the (n−1) shell contributes 0.85, every electron in the (n−2) or lower shells contributes 1.00, and electrons in groups to the right contribute 0. For an electron in an nd or nf group, every other electron in the same group contributes 0.35, every electron in all groups to its left contributes 1.00, and groups to the right contribute 0. Z∗=Z−S. Iron is (1s)2(2s,2p)8(3s,3p)8(3d)6(4s)2. The ratio Z∗(3p)/Z∗(3d) for iron is:
A0.42
B2.36
C2.02
D4.16
Answer: B
3p electron: S=7(0.35)+8(0.85)+2(1.00)=11.25 (the 3d and 4s groups lie to the right and add nothing), Z∗=14.75. 3d electron: Z∗=6.25. Ratio =2.36.