1.0 mol of Xe reacts completely with 1.6 mol of F2 to give only XeF2 and XeF4 (all Xe and all F2 used up). Molar masses:

Question

1.0 mol of Xe reacts completely with 1.6 mol of F2 to give only XeF2 and XeF4 (all Xe and all F2 used up). Molar masses: Xe 131, F 19, so XeF4 = 207 g mol^-1. The mass of XeF4 formed is

Accepted Answer

124.2 g

Answer

82.8 g

Answer

62.1 g

Answer

165.6 g

$1.0$ mol of Xe reacts completely with $1.6$ mol of $F X_{2}$ to give only $XeF X_{2}$ and $XeF X_{4}$ (all Xe and all $F X_{2}$ used up). Molar masses: Xe 131, F 19, so $XeF X_{4}$ = 207 $g mo l^{- 1}$ . The mass of $XeF X_{4}$ formed is

Answer: D

More questions on Structures and hybridisation of xenon compounds

1.0 mol of Xe reacts completely with 1.6 mol of FX2​ to give only XeFX2​ and XeFX4​ (all Xe and all FX2​ used up). Molar masses: Xe 131, F 19, so XeFX4​ = 207 g mol−1. The mass of XeFX4​ formed is

Answer: D

More questions on Structures and hybridisation of xenon compounds

$1.0$ mol of Xe reacts completely with $1.6$ mol of $F X_{2}$ to give only $XeF X_{2}$ and $XeF X_{4}$ (all Xe and all $F X_{2}$ used up). Molar masses: Xe 131, F 19, so $XeF X_{4}$ = 207 $g mo l^{- 1}$ . The mass of $XeF X_{4}$ formed is