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NEET levelSingle correct optionDifficulty 1 of 3ph117

The hybridisation of Xe in $XeF X_{2}$ is

A $s p$
B $s p^{3} d^{2}$
C $s p^{3}$
D $s p^{3} d$

Answer: D

Xe has 2 bond pairs and 3 lone pairs, giving 5 electron pairs and hence 5 hybrid orbitals. This is

s p^{3} d

, with a trigonal bipyramidal arrangement and the three lone pairs equatorial, so the molecule is linear.

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