Answer: A, B, C
XeFX6 acts as a fluoride acceptor with RbF and as a fluoride donor with BFX3. XeFX5X+ has 8+35−1=42 valence electrons, the same as IFX5 (7+35), and both are square pyramidal with one lone pair. XeFX7X− has 8+49+1=58 valence electrons while IFX7 has 7+49=56, so they are not isoelectronic. Options 1, 2 and 3 are correct.