Consider these statements. (i) $XeF X_{2}$ , $XeF X_{4}$ and $XeF X_{6}$ are colourless crystalline solids that sublime readily at room temperature. (ii) All three are strong fluorinating agents. (iii) Complete hydrolysis of $XeF X_{6}$ to $XeO X_{3}$ is a redox reaction. (iv) Hydrolysis of $XeF X_{4}$ is a redox reaction. The number of correct statements is

Answer: C

(i) and (ii) are true. (iii) is false because Xe stays +6 in

XeF X_{6} + 3 H X_{2} O XeO X_{3} + 6 HF

. (iv) is true because XeF4 gives Xe,

XeO X_{3}

and

O X_{2}

. So 3 statements are correct.