JEE Main levelSingle correct optionDifficulty 2 of 3ph128
In the hydrolysis of XeFX4 the xenon(IV) undergoes disproportionation into
AXe(II) and Xe(IV)
BXe(0) and Xe(VIII)
CXe(0) and Xe(VI)
DXe(II) and Xe(VI)
Answer: C
The reaction is 6XeFX4+12HX2O4Xe+2XeOX3+24HF+3OX2. Xenon appears as Xe (oxidation state 0) and as XeOX3 (+6), so Xe(IV) disproportionates to Xe(0) and Xe(VI).