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NEET levelSingle correct optionDifficulty 1 of 3ph115

In 1962 Neil Bartlett tried the reaction of xenon with $PtF X_{6}$ because the first ionisation enthalpy of Xe ( $1170 kJ mo l^{- 1}$ ) is very close to that of

Amolecular oxygen
Bmolecular chlorine
Cmolecular nitrogen
Dmolecular hydrogen

Answer: A

PtF X_{6}

oxidises

O X_{2}

(ionisation enthalpy about

1175 kJ mo l^{- 1}

) to give

O X_{2} X^{+} [PtF X_{6}] X^{-}

. Since Xe has almost the same ionisation enthalpy, Bartlett expected, and obtained, a red solid first formulated as

Xe X^{+} [PtF X_{6}] X^{-}

. The answer is molecular oxygen.

Practice p-Block Elements: Groups 17 and 18 More on Noble gases: xenon fluorides, oxides and oxyfluorides

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