In the reaction of chlorine with hot concentrated NaOH, 3Cl2 + 6NaOH -> 5NaCl + NaClO3 + 3H2O, the ratio of the number of chlorine atoms oxidised to the number reduced is

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JEE Advanced levelSingle correct optionDifficulty 3 of 3ph034

In the reaction of chlorine with hot concentrated $NaOH$ , $3 Cl X_{2} + 6 NaOH 5 NaCl + NaClO X_{3} + 3 H X_{2} O$ , the ratio of the number of chlorine atoms oxidised to the number reduced is

A1 : 5
B1 : 1
C5 : 1
D3 : 5

Answer: A

Six Cl atoms enter. One goes from 0 to +5 (oxidised, 5 electrons lost). Five go from 0 to -1 (reduced, 5 electrons gained), which balances the electrons. So the ratio is 1 : 5.

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In the reaction of chlorine with hot concentrated NaOH, 3ClX2​+6NaOH​5NaCl+NaClOX3​+3HX2​O, the ratio of the number of chlorine atoms oxidised to the number reduced is

Answer: A

More questions on Trends in halogens

In the reaction of chlorine with hot concentrated $NaOH$ , $3 Cl X_{2} + 6 NaOH 5 NaCl + NaClO X_{3} + 3 H X_{2} O$ , the ratio of the number of chlorine atoms oxidised to the number reduced is