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MolSynapse / Question bank / p-Block Elements: Groups 15 and 16 / Oxygen, ozone and oxides

JEE Main levelSingle correct optionDifficulty 2 of 3pn192

Sodium peroxide (7.8 g, 78 g/mol) reacts with excess water: $2 Na X_{2} O X_{2} + 2 H X_{2} O 4 NaOH + O X_{2}$ . The volume of $O X_{2}$ at STP (22.4 L/mol) is

A1.12 L
B3.36 L
C2.24 L
D0.56 L

Answer: A

Moles of

Na X_{2} O X_{2}

= 7.8/78 = 0.10. Two moles of peroxide give one mole of

O X_{2}

, so 0.05 mol forms. Volume =

0.05 \times 22.4 = 1.12

L.

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