Lead sulphide is oxidised by ozone to lead sulphate. In PbS + O3 -> PbSO4 + O2, the number of moles of O3 needed per mole of PbS is

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Lead sulphide is oxidised by ozone to lead sulphate. In $PbS + O X_{3} PbSO X_{4} + O X_{2}$ , the number of moles of $O X_{3}$ needed per mole of $PbS$ is

Sulphur goes from

- 2

+ 6

, a loss of 8 electrons. Each

O X_{3}

accepts 2 electrons (one O atom goes to

- 2

, the rest leaves as

O X_{2}

). So

PbS + 4 O X_{3} PbSO X_{4} + 4 O X_{2}