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JEE Advanced levelSingle correct optionDifficulty 3 of 3pn106

9.2 g of $NO X_{2}$ is completely absorbed in excess cold aqueous NaOH: $2 NO X_{2} + 2 NaOH NaNO X_{2} + NaNO X_{3} + H X_{2} O$ . Taking N = 14, O = 16, Na = 23, the total mass of the two sodium salts formed is

A15.4 g
B30.8 g
C7.7 g
D8.5 g

Answer: A

Moles

NO X_{2}

=

9.2/46 = 0.20

. Two moles of

NO X_{2}

give one mole each of

NaNO X_{2}

(69 g/mol) and

NaNO X_{3}

(85 g/mol), so 0.10 mol of each is formed. Mass =

0.10 \times 69 + 0.10 \times 85 = 15.4

g.

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