JEE Advanced levelSingle correct optionDifficulty 3 of 3pn091
A sample of SOX2 is bubbled through acidified KMnOX4 solution until 100 mL of 0.200 M KMnOX4 is just decolourised (5SOX2+2MnOX4X−+2HX2O5SOX4X2−+2MnX2++4HX+). The volume of SOX2 at STP (22.4 L/mol) absorbed is
A0.448 L
B0.56 L
C2.24 L
D1.12 L
Answer: D
Moles MnOX4X− = 0.200×0.100=0.0200. From the equation moles SOX2 = 0.0200×5/2=0.0500. Volume = 0.0500×22.4=1.12 L.