JEE Advanced levelSingle correct optionDifficulty 3 of 3pb199
Nickel tetracarbonyl, Ni(CO)X4, formed from CO and nickel, has the following oxidation state of Ni, geometry and magnetic behaviour:
A0, tetrahedral, paramagnetic
B+4, tetrahedral, diamagnetic
C0, tetrahedral, diamagnetic
D0, square planar, paramagnetic
Answer: C
CO is a neutral ligand, so Ni is in oxidation state 0 (3d10 after the 4s electrons move into 3d). Four CO ligands donate into sp3 hybrid orbitals, giving a tetrahedral complex. With no unpaired electrons it is diamagnetic.