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JEE Advanced levelSingle correct optionDifficulty 3 of 3pb123

Match Column I with Column II. Column I: (P) Tl, (Q) Sn, (R) graphite, (S) . Column II: (1) most stable oxidation state is +1, (2) layered sp2 carbon that conducts electricity, (3) forms an amphoteric dioxide, (4) electron-deficient molecule that accepts an electron pair.

  1. AP-1, Q-3, R-2, S-4
  2. BP-3, Q-1, R-2, S-4
  3. CP-1, Q-2, R-3, S-4
  4. DP-1, Q-3, R-4, S-2

Answer: A

Tl shows the inert pair effect (1). is amphoteric (3). Graphite has delocalised electrons in sp2 layers (2). has an incomplete octet and is a Lewis acid (4). So P-1, Q-3, R-2, S-4.
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