Which of the following statements about tin and lead metals and their hydroxides are correct?

ATin dissolves in hot concentrated $HCl$ to give $SnCl X_{2}$ and $H X_{2}$ .
BLead is attacked only superficially by dilute $HCl$ and dilute $H X_{2} SO X_{4}$ because an insoluble $PbCl X_{2}$ or $PbSO X_{4}$ film forms.
CGaseous $SnCl X_{2}$ is a linear molecule.
D $Pb (OH) X_{2}$ dissolves in excess NaOH to give a plumbite.

Answer: A, B, D

Tin is above hydrogen in the electrochemical series and gives

SnCl X_{2} + H X_{2}

with hot conc. HCl. The insoluble surface film protects lead. Gaseous

SnCl X_{2}

has a lone pair on Sn (

s p^{2}

-like, bent), so it is not linear.

Pb (OH) X_{2} + 2 NaOH Na X_{2} PbO X_{2} + 2 H X_{2} O

, which shows amphoteric character. Statements 1, 2 and 4 are correct.