Answer: A, B, D
The compound is trans-1-bromo-2-isopropylcyclohexane. Bromine must be axial, which forces the trans isopropyl group axial too, so the C-2 hydrogen is equatorial and only the C-6 axial hydrogen is anti to bromine; the alkene formed is 3-isopropylcyclohexene, not 1-isopropylcyclohexene. In the cis isomer bromine is axial with isopropyl equatorial, leaving an axial C-2 hydrogen anti to bromine and giving the Saytzeff alkene.