The meso compound shown loses one molecule of HBr (anti E2) on treatment with a strong base. Which structure is the 1-bromo-1,2-diphenylethene formed?

The compound is meso-1,2-dibromo-1,2-diphenylethane. With H on one carbon anti to Br on the other, the two phenyl groups end up cis, so the bromine on the remaining carbon is trans to the phenyl on the other carbon, which is the (E)-alkene. The chiral (R,R) or (S,S) dibromide would give the (Z)-alkene. Diphenylacetylene needs a second elimination and stilbene would need loss of Br2.