MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Organic Reaction Mechanisms IV: Elimination
/
Substitution vs elimination competition
NEET level
Single correct option
Difficulty 1 of 3
o4150
To convert bromoethane mainly into ethene, the best conditions are
A
alcoholic
KOH
, heat
B
aqueous
KOH
, warm
C
NaI
in acetone
D
dilute
HCl
, room temperature
Answer: A
Alcoholic
KOH
gives the strongly basic ethoxide and favours dehydrohalogenation to ethene. Aqueous
KOH
favours substitution to ethanol.
Practice Organic Reaction Mechanisms IV: Elimination
More on Substitution vs elimination competition
Previous question
Next question
More questions on Substitution vs elimination competition
Assertion (A): Sodium ethoxide converts 2-bromo-2-methylpropane mainly into 2-methylpropene, while 1-bromopropane gives mainly propyl ethyl ...
JEE Advanced level
Potassium tert-butoxide, (CH3)3COK, favours elimination over substitution with alkyl halides mainly because it is
NEET level
1-Bromopropane is treated with NaI in acetone. The major product is
NEET level
2-Bromo-2-methylpropane is heated with NaOEt in ethanol. The major product is
JEE Main level
2-Bromo-2-methylbutane is heated with (CH3)3COK in (CH3)3COH. The major alkene is
JEE Main level
1-Bromopropane is treated with NaCN in DMSO at room temperature. The major product is
JEE Main level