1-Bromopropane is treated with $NaI$ in acetone. The major product is

Apropene
B1-iodopropane
Cpropan-1-ol
D2-iodopropane

Answer: B

Iodide is a good nucleophile and a very weak base, and acetone is a polar aprotic solvent. A primary halide therefore reacts by SN2 (Finkelstein reaction) giving 1-iodopropane.

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1-Bromopropane is treated with NaI in acetone. The major product is

Answer: B

More questions on Substitution vs elimination competition

1-Bromopropane is treated with $NaI$ in acetone. The major product is