Answer: A, B, C
Without a strong base the substrate ionises (SN1/E1) and the cation is captured by solvent ethanol more often than it loses a proton, so the ether predominates. With unhindered ethoxide, E2 follows Saytzeff orientation. With the bulky tert-butoxide, Hofmann orientation gives 2-methylbut-1-ene. Ethanol is neither a bulky nor a strong base, and in E1 the Saytzeff alkene is favoured, so the fourth statement is false.