2-Bromopropane is treated with $NaI$ in acetone. The major product is

Apropane
Bpropene
Cpropan-2-ol
D2-iodopropane

Answer: D

Iodide is an excellent nucleophile but a very weak base, and acetone is a polar aprotic solvent that leaves it unsolvated. These conditions favour SN2 (the Finkelstein reaction) over E2, so 2-iodopropane is formed.

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2-Bromopropane is treated with NaI in acetone. The major product is

Answer: D

More questions on Substitution vs elimination competition

2-Bromopropane is treated with $NaI$ in acetone. The major product is