Answer: A
Hofmann elimination is an anti E2, so the trimethylammonium group and the beta hydrogen must be trans-diaxial. In the reactive trans-diaxial chair, the methyl on C-2 is axial and C-2 has no axial hydrogen, so only the axial hydrogen on C-6 is anti. Removal of it gives the C-1=C-6 alkene, 3-methylcyclohexene, which is also the Hofmann-type product.