A 30.2 g sample (0.200 mol, M = 151 g/mol) of 2-bromo-2-methylbutane is subjected to two separate E2 runs. In run (i), $(\mathrm{CH}{}_3){}_3\mathrm{COK}$/$(\mathrm{CH}{}_3){}_3\mathrm{COH}$ converts 95 percent of the bromide to alkenes, of which 72 percent is 2-methylbut-1-ene. In run (ii), $\mathrm{NaOEt}$/ethanol converts 80 percent of the bromide to alkenes, of which 30 percent is 2-methylbut-1-ene. By how many grams does the mass of 2-methylbut-1-ene (M = 70 g/mol) in run (i) exceed that in run (ii)? Give the answer to two decimal places.

Numerical answer type, tolerance 0.05.