Answer: A, B
The compound is neopentyl bromide. Ionisation is accompanied (or immediately followed) by a 1,2-methyl shift, so a discrete primary cation is not required. The tertiary cation formed can lose a proton to give 2-methylbut-2-ene. The main substitution product is the rearranged 2-ethoxy-2-methylbutane, not the unrearranged ether, and ionisation is much slower than for tert-butyl bromide. Correct: first two.