Answer: B
The compound is 3,3-dimethylbutan-2-ol (pinacolyl alcohol). Protonation and loss of water gives a secondary cation next to a quaternary carbon. A 1,2-methyl shift gives the tertiary 2,3-dimethylbutan-2-yl cation, which captures bromide to give 2-bromo-2,3-dimethylbutane, CC(C)(Br)C(C)C.