Answer: A, B, C
The compound is (R)-butan-2-ol. Tosylation leaves the C-O bond intact, so the tosylate keeps the arrangement. SXN2 by bromide inverts it, giving (S)-2-bromobutane (S). PBrX3 also converts a secondary alcohol by SXN2 displacement of the activated oxygen, giving the same (S)-bromide. Concentrated HBr proceeds largely by SXN1/mixed pathways with substantial racemisation, not clean retention. Correct: first three.