The primary allylic chloride shown (double bond geometry not specified) can react by either pathway. Select all correct statements.

The compound is 1-chlorobut-2-ene (crotyl chloride). Its $\mathrm{S}{}_{\mathrm{N}}2$ transition state is stabilised by overlap with the adjacent pi system, so it is faster than 1-chlorobutane. Its $\mathrm{S}{}_{\mathrm{N}}1$ cation is the allyl cation $\mathrm{CH}{}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}{}_2{}^{+}\leftrightarrow \mathrm{CH}{}_3-\mathrm{CH}{}^{+}-\mathrm{CH}=\mathrm{CH}{}_2$, so water can attack at either end and give two constitutionally isomeric alcohols. The halogen is on an $s{p}^3$ carbon, so $\mathrm{S}{}_{\mathrm{N}}2$ is possible, and the cation is resonance stabilised, not an unstabilised primary one. Correct: the first two.