Answer: B
(i) Under acid the benzylic C-O bond is loosened, methanol attacks the benzylic carbon from the back, and CX6HX5−CH(OCHX3)−CHX2OH forms with inverted geometry. Its priorities are OCHX3>CHX2OH (O,H,H) >CX6HX5 (C,C,C) >H, and the CIP calculation gives R. (ii) Methoxide attacks CHX2, so the stereocentre of CX6HX5−CH(OH)−CHX2OCHX3 keeps its geometry, with priorities OH>CHX2OCHX3>CX6HX5>H, giving S. Both assignments were checked with a CIP calculation.