Answer: B
A secondary alcohol in strong HBr (a poor SN2 setting, with a hindered beta branch) ionises to the secondary cation (CHX3)X2CH−CHX+−CHX3. A 1,2-hydride shift from the neighbouring tertiary C-H gives the more stable tertiary cation (CHX3)X2CX+−CHX2CHX3, which captures bromide to give 2-bromo-2-methylbutane. This has no stereocentre, so the original configuration is lost and the product is optically inactive.