For the hydrolysis of (CH3)3C-Br in aqueous acetone containing NaOH, choose the correct statement(s).

The rate-determining step produces a planar carbocation.

Tripling [OH-] at constant [RBr] triples the rate.

The rate-determining step produces a planar carbocation.

The rate-determining step is a collision between OH- and RBr.

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3o3045

For the hydrolysis of $(CH X_{3}) X_{3} C - Br$ in aqueous acetone containing $NaOH$ , choose the correct statement(s).

SN1: the slow step is unimolecular ionisation to a planar tertiary cation, so the rate is

k [RBr]

(statements 1 and 3 are true). The rate is independent of

[OH X^{-}]

, so tripling it does nothing (statement 2 false), and no bimolecular collision is involved in the slow step (statement 4 false).