Answer: D
Protonation turns OH into the leaving group HX2O and ionisation gives the secondary cation CHX3−CHX+−C(CHX3)X3. A 1,2-methyl shift gives the tertiary cation (CHX3)X2CX+−CH(CHX3)X2, which bromide captures to give (CHX3)X2CBr−CH(CHX3)X2, 2-bromo-2,3-dimethylbutane. (Unrearranged 2-bromo-3,3-dimethylbutane is only a minor product.)