JEE Main levelSingle correct optionDifficulty 2 of 3o3028
Arrange the leaving groups ClX−, CHX3COOX−, OHX− and NHX2X− in decreasing order of leaving-group ability.
AClX−>CHX3COOX−>OHX−>NHX2X−
BNHX2X−>OHX−>CHX3COOX−>ClX−
CCHX3COOX−>ClX−>OHX−>NHX2X−
DClX−>OHX−>CHX3COOX−>NHX2X−
Answer: A
Leaving ability parallels the acidity of the conjugate acid: HCl (pKa about −7), CHX3COOH (4.8), HX2O (15.7) and NHX3 (about 38). The weaker the base, the better the leaving group, giving the order ClX−>CHX3COOX−>OHX−>NHX2X−.